DLL - Append

void DLL::append(int data){

   if(_tail != NULL){
  _tail->_next = new Node(data, _tail->_prev, _tail);
   }
}

Oopers Group 8 - Wiki Team Page

Go Team 8 of OOP344 Winter 2013 Semester. First time doing a wiki page, and it looks pretty decent job if I don't say so myself : http://zenit.senecac.on.ca/wiki/index.php/OOP344_20131_Oopers

OOP344 Week2 Environmental Variable Search and Display

// OOP344 Week2 Environmental Variable Search and Display -- Peter Huang
// Program finds a user entered environmental variable (case insensitive). It displays
// the variable and the value/path of the data.

#include <iostream>
#include <cstring>
using namespace std;

// #define DEBUG
#define usrMAX strlen(argv[1])
#define arrMAX strlen(env[arr])

int main(int argc, char* argv[], char* env[])
{
    int i;
    int j;
    int arr;
    int pos;
    int flag = 0;
    char usrSearch[usrMAX+1];

    strcpy(usrSearch,argv[1]); // copy search string to user search array

    char searchEnv[usrMAX+1];

    for(i = 0; env[i] && flag == 0; i++)
    {
         if(flag == 0) // loops and passes environmental variable string element, only to the length of user search array
         {
             for(j = 0; j < usrMAX; j++)
                searchEnv[j] = env[i][j];
             searchEnv[j] = '\0';

             if(stricmp(usrSearch,searchEnv) == 0) // index the env array and pos when user search and environmental name match (case insensitive)
             {
                 pos = j;
                 arr = i;
                 flag = 1;
             }
         }
    }

    if(flag == 1) // when match, finds which environmental index and the last pos (the actual data/path) and passes into a value array to output.
    {
        char searchVal[arrMAX];

        for(i = 0; i < arrMAX; i++)
        {
            if(env[arr][pos+i] != '\0')
              searchVal[i] = env[arr][pos+i];
        }
        searchVal[i] = '\0';

        cout << searchEnv << searchVal << endl;
    }
    else
        cout << "Not found" << endl;

#ifdef DEBUG // fardad's code for listing environmental variables
    for(i=0;env[i] != 0;i++){
        cout<<i<<": "<<env[i]<<endl;
    }
#endif

    return 0;
}

OOP344 Week2 Command Line Exercises

An exercise on week2 of Oop344 of all operations using commandline.


Add Command Line
// OOP344 Week2 Exercise Peter Huang CMDL Add
#include <iostream>
#include <sstream>
#include <cstdlib>
using namespace std;

int main(int argc, char* argv[], char* env[]) {
  int sum = 0;
  if(argc != 3)
      cout << "Not valid add command. Command format is : add num1 num2" <<endl;
  else{
      for(int i = 1; i < argc; i++)
          sum = sum + atoi(argv[i]);
      cout << "Sum : " << sum <<endl;
  }
  return 0;
}


Subtract Command Line
// OOP344 Week2 Exercise Peter Huang CMDL Subtract
#include <iostream>
#include <sstream>
#include <cstdlib>
using namespace std;

int main(int argc, char* argv[], char* env[]) {
  int dif = 0;
  if(argc != 3)
      cout << "Not valid subtract command. Command format is : sub num1(to) num2(from)" <<endl;
  else {
      dif = atoi(argv[1]) - atoi(argv[2]);
      cout << "Difference : " << dif <<endl;
  }
  return 0;
}


Multiplication Command Line
// OOP344 Week2 Exercise Peter Huang CMDL Multiply
#include <iostream>
#include <sstream>
#include <cstdlib>
using namespace std;

int main(int argc, char* argv[], char* env[]) {
  int ans;
  if(argc != 3)
      cout << "Not valid multiplication command. Command format is : mul num1 num2" <<endl;
  else {
      ans  = atoi(argv[1]) * atoi(argv[2]);
      cout << "Answer(Multiplication) : " << ans <<endl;
  }
  return 0;
}

 
Division Command Line
// OOP344 Week2 Exercise Peter Huang CMDL Divide
#include <iostream>
#include <sstream>
#include <cstdlib>
using namespace std;

int main(int argc, char* argv[], char* env[]) {
  double ans;
  if(argc != 3)
      cout << "Not valid division command. Command format is : div num1(numerator) num2(denominator)" <<endl;
  else  {
      ans  = double(atoi(argv[1])) / atoi(argv[2]);
      cout.precision(2);
      cout << "Answer(Division) : " << ans <<endl;
  }
  return 0;
}